Part A Why does the resultant tide-generating force create a...

Part A Why does the resultant tide-generating force create a tidal bulge on the side of Earth that faces away from the Moon? ? View Available Hint(s) The centripetal force is weaker than the gravitational force at the zenith. The centripetal force exceeds gravitational force at the zenith. The centripetal force is equal to the gravitational force at both the zenith and nadir. The centripetal force is weaker than the gravitational force at the nadir. Centripetal force exceeds gravitational force at the nadir, or the point on Earth furthest from the Moon.

Transcript

00:01 In the first part of this problem, we have to determine the force that exerts, that is exerted by the moon and sun on the mess of water on earth.

00:09 So let the force exerted by sun is fs, and the force exerted by moon is fm.

00:19 So using the newton's law of gravitation, we can white fs equals to capital g, ms, small and divided by rh square.

00:34 We call it equation number 1.

00:36 Here this g is the gravitational constant, ms is the mass of sun, m is the mass of water on earth, and this r is the distance between these two masses.

00:44 So by inserting values into this equation we can write fs equals to 6 .67 multiplied by eternalized power minus 11 newton meter square per kg square into the mass of sun is 1 .99 multiplied returners power 30 kg into m divided by this rs has the value of 1 .50 multiply by 10 raise power 11 meter and there is square on it so this will give us the value for this f s f s equals to 5 .90 multiply by turnres power minus 3 newton into m.

01:52 Similarly we can write the relation for fm as fm equals to capital g m m m divided by rm square and we call it equation number two now by inserting values into this equation we can write fm that is the force exerted by moon on the water on earth is equals to 6 .67 multiplied turn raise bar minus 11 newton meter square per kg square into and the mass of moon is 7 .33 x .m .2 x .m .2 kg into m divided by and the distance between these two masses is 3 .80 multiplied by 10x bar.

02:53 8 meter and there is square or not on it so this will give us the value for this fm as fm equals to 3 .40 multiply by 10x bar minus 5 newton into m where this m is the mass of water on earth now in second part of this problem we have to calculate the ratio of these two forces that is f s divided by fm.

03:39 Now let's take the ratio of these two forces.

03:42 So f s divided by fm is equals to a 5 .90 multiply by tenor power minus three newton into m divided by the value for this fm as 3 .40 multiply by tenor power minus 5 newton into so this will give you the value for f s fs is fs equals to one hundred and seventy three times of fm so we can say that the force exerted by the sun is 173 times greater than this the force exerted by a moon on the water of water on the surface of earth now in part see of this problem we have to calculate the force the difference of the forces on the mass of water a two opposite sides.

04:47 But the difference of these two forces is f.

04:55 So we can write f as f equals to f near that is fn minus f4 that is f f.

05:08 So we call it equation number three.

05:12 Now we can write using the newton's law of gravitation...

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