Part A Write down the equation for pressure as a function of...

Part A Write down the equation for pressure as a function of depth in a liquid. Express your answer in terms of the air pressure $p_0$ above the water surface, the gravitational acceleration $g$, the depth $h$ and the density $\rho_w$ of the water. $\text{p(h)} =$ Submit Part B Select the forces acting on the cube. Select all that apply. The gravitational force The normal force The surface-tension force The kinetic friction force The buoyant force

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00:01 This question has four sub questions.

00:02 Let us solve one by one.

00:03 The first sub question is asking to find an expression for the difference between the fluid pressure adding on the bottom surface of the cube and the fluid pressure adding on the top surface of the cube.

00:12 First let us have the given the mass of the cube.

00:18 M is 580 kages density of water, let us represent with row, is 1 .04 multiplied by gram per centimeter cube.

00:30 In kg per meter cube we get 1 .04 multiplied by 10 power minus 3 divided by 10 power minus 6 kg per meter cube.

00:44 We get 1 .04 multiplied by 10 power 3 kg per meter cube.

00:50 The length of the cube l is 1 .7 meter.

00:55 The depth from the surface of 2 to top of the cube is d is 1 .8 meter.

01:01 If you draw the diagram, we get for the first version which is asking to find expression of difference in pezzles from the top surface and bottom surface of q.

01:12 If p0 is an atmosphere pressure, we know generally in a liquid, it additions to d on the surface.

01:18 We get the pressure acting is row gd.

01:23 Similarly, the pressure acting on top surface is p top.

01:27 It is equal to collective pressure, atmosphere pressure plus row gd.

01:32 And p bottom is p not plus rho g...

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