Part A A right angle made of two tiny rods is hung by a...

Part A A right angle made of two tiny rods is hung by a string as in the figure below. The mass of the rods is proportional to their lengths. The ratio of b to a is 1.90. What is the angle ?? Express your answer in degrees.

Transcript

00:01 Hello everyone in this question one figure is given and we can draw the 3b2 diagram of the figure first so now let's draw the fibrodi diagram of the given figure so this is the pivot diagram of the given figure and here we need to find out the value of angle theta so let mass of rot be m suffix a and m suffix b so here you can intern as m suffix a comma m suffix b equals to mass of rot and here the system is in equilibrium so therefore from here you can train as summation of tau equals to 0 so now therefore from here you can train as m suffix a multiplied by g multiplied by a divided by 2 multiplied by sine alpha minus m suffix b multiplied by g multiplied by b divided by 2 multiplied by sine beta equals to 0 so therefore further solving this from here we will get m suffix a multiplied by a multiplied by sine alpha equals to m suffix b multiplied by b multiplied by sine beta so therefore in the question we know that alpha plus beta equals to 90 degree and from here we will get beta equals to 90 degree minus alpha so therefore from here you can see that m a directly proportional to a and m suffix b directly proportional to b so from here let's take m suffix a equals to k multiplied by a and m suffix b equals to k multiplied by b so where k is an arbitrary monster therefore further solving this from here we will get m suffix b divided by m suffix a equals to k multiplied by b divided by km multiplied by a so here k and k cancel out so therefore further following this from here we will get b divided by a which is equal to we will get 1 .30 so therefore from here we will get m suffix b equals to 1 .30 times of m suffix a so therefore now we will put the value in the above equation so therefore from here we will get m suffix a a sine alpha equals to 1 .30 multiplied by m a multiplied by 1 .30 multiplied by a multiplied by sign 90 degree minus alpha so therefore further solving this from here we will got m suffix a multiplied by a sine alpha equals to 1 .30 whole squared multiplied by m suffix a multiplied by a multiplied by cost alpha so therefore further solving this from here we will get fine alpha divided by os of alpha equals to 1 .30 whole squared so further solving this from here we will get 10 of alpha equals to 1 .30 polysquare so therefore further solving this from here we will got the value of alpha equals to 10 inverse of 1 .30 polysquare.

03:37 So here we have to find the value of theta.

03:39 So theta you can retain as theta equals to 180 degree minus alpha...

Question

Part A A right angle made of two tiny rods is hung by a string as in the figure below. The mass of the rods is proportional to their lengths. The ratio of b to a is 1.90. What is the angle ?? Express your answer in degrees.

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