00:01
Okay, in this problem we're asked to consider this reaction and we're carrying out, carrying it out as described in experiment and we have 0 .636 grams of magnesium.
00:14
We determined we find our heat for the reaction to equal 5 .12 kilojoules and we're asked to, no, that's not find, we found, okay, and now we have to calculate kilojoules per mole of magnesium.
00:52
Okay, easy peasy.
00:54
0 .636 grams of magnesium.
01:01
I'm actually gonna do it like this.
01:03
5 .12 kilojoules per 0 .636 grams of magnesium.
01:18
So now let me get to my periodic table so i get the right molar mass, 24 .31 and this will equal, let me do this, 5 .12 times 24 .31 divide 0 .636 and i get 195 .7 kilojoules per mole and let me go look at my sig figs for my periodic table.
01:55
I have three and three.
01:57
So i'm gonna report this as 196 kilojoules per mole of magnesium.
02:12
Okay, and this will be negative, i think...