00:01
Hello students, we need to find out the volume of carbon dioxide for which mass of butane is given which is 2 .80 gram and we know that molar mass for butane is 58 .12 gram per mole.
00:28
Pressure is given which is 1 atm and temperature is 23 degree celsius.
00:35
So, we'll convert it into calvins by adding 273 to it.
00:41
So, this will be 296 calvin.
00:45
Now, first of all calculate the number of moles of butane.
00:49
So, we know that number of moles is equals to given mass divided by molar mass.
01:03
So, number of butane will be 2 .80 divided by 58 .12.
01:15
So, this will be equals to 0 .04 mole.
01:21
Now, from the reaction we can see that 2 mole of c4h10 produces 8 mole of carbon dioxide...