Question

Part a The shaft shown in Fig 2a has a diameter of 75mm. Calculate the maximum shear stress induced and the angle of twist per metre when subjected to a torque of 4520Nm. [G = 80GN/m²] [8] Part b Determine the maximum allowable internal diameter if the solid shaft is replaced by a larger, hollow shaft of external diameter 100mm, if the maximum shear stress induced is not to exceed that in part a. (torque remains the same). Determine the percentage saving in material which results from using the larger hollow shaft. Determine also the corresponding percentage reduction in the angle of twist. [12]

          Part a
The shaft shown in Fig 2a has a diameter
of 75mm. Calculate the maximum shear
stress induced and the angle of twist per
metre when subjected to a torque of
4520Nm. [G = 80GN/m²]
[8]
Part b
Determine the maximum allowable internal
diameter if the solid shaft is replaced by a
larger, hollow shaft of external diameter
100mm, if the maximum shear stress
induced is not to exceed that in part a.
(torque remains the same).
Determine the percentage saving in
material which results from using the
larger hollow shaft.
Determine also the corresponding percentage reduction in the angle of twist.
[12]

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Part a
The shaft shown in Fig 2a has a diameter
of 75mm. Calculate the maximum shear
stress induced and the angle of twist per
metre when subjected to a torque of
4520Nm. [G = 80GN/m²]
[8]
Part b
Determine the maximum allowable internal
diameter if the solid shaft is replaced by a
larger, hollow shaft of external diameter
100mm, if the maximum shear stress
induced is not to exceed that in part a.
(torque remains the same).
Determine the percentage saving in
material which results from using the
larger hollow shaft.
Determine also the corresponding percentage reduction in the angle of twist.
[12]

Added by Sandra A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Stephen Zaffke

Step 1

075 m) G = Shear modulus (80 GN/m = 80 * 10^9 N/m) J = Polar moment of inertia (π * d^4 / 32) L = Length of the shaft (1 m) Let's calculate each value: Maximum shear stress (τ) = (16 * 4520) / (π * (0.075)^3) ≈ 1.45 MPa J = π * (0.075)^4 / 32 ≈ 1.77 * 10^-7 Show more…

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Part a: The shaft shown in Fig 2a has a diameter of 75mm. Calculate the maximum shear stress induced and the angle of twist per meter when subjected to a torque of 4520Nm. [G=80GN/m] [8] Fig. 2a: T=4520N.m Part b: Determine the maximum allowable internal diameter if the solid shaft is replaced by a larger hollow shaft with an external diameter of 100mm, if the maximum shear stress induced is not to exceed that in part a (torque remains the same). Fig. 2b: Determine the percentage saving in material which results from using the larger hollow shaft. Determine also the corresponding percentage reduction in the angle of twist. [12]

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