Question

Partial list of opcodes: 0001 - Load AC from memory 0010 = Store AC to memory 0101 - Add to AC from memory Partial program execution is as illustrated: \begin{tabular}{|c|c|c|c|} \hline Meanory & CPU Registers & Menory & CPU Registers \\ \hline 5001942 & 500 PC & 5001 9 4 2. & \( \square \mathrm{PC} \) \\ \hline 5015943 & & 3015943 & AC \\ \hline 5022943 & 1942 R & 5022943 & \( \mathbb{R} \) \\ \hline & 1 & & 2 \\ \hline Memory & CPU Registers & Memory & CPU Registers \\ \hline \multirow[t]{3}{}{\[ \begin{array}{l} 5001942 \\ 501594+3 \\ 5029.43 \end{array} \]} & \multirow[t]{3}{}{} & \multirow[t]{2}{}{} & \multirow[t]{2}{}{\( \square \mathrm{PC} \) PC} \\ \hline & & & \\ \hline & & & \\ \hline \[ 942 \begin{array}{llll} 0 & 0 & 0 & 5 \\ 943 \\ \hline 0 & 0 & 0 & 2 \end{array} \] & 3 & & 4 \\ \hline Memory & \multirow[t]{2}{}{CPU Registers \( \square \) PC} & Memory & \multirow[t]{2}{}{\begin{tabular}{l} CPU Registers \\ \( \square \mathrm{PC} \) \end{tabular}} \\ \hline \[ 5 0 0 \longdiv { 1 9 + 2 } \] & & 50019 1 9 & \\ \hline 50159 5 43 & & 5015 & AC \\ \hline 5022943 & & \( 5 0 2 \longdiv { 2 9 4 3 } \) & R \\ \hline 94300042 & 5 & 943 & 6 \\ \hline \end{tabular} What do the following contain? In step 2: Program Counter: PC in step 2 = \( \square \) Accumulator: AC in step 2 - \( \square \) In satep 6: Program Counter: PC in step \( 6= \) \( \square \) Accumulator: \( A C \) in step \( 6= \) \( \square \) Instruction Register: IR in step 6 = \( \square \) Location \( 942= \) \( \square \) Location 943 = \( \square \)

          Partial list of opcodes:
0001 - Load AC from memory
0010 = Store AC to memory
0101 - Add to AC from memory
Partial program execution is as illustrated:
\begin{tabular}{|c|c|c|c|}
\hline Meanory & CPU Registers & Menory & CPU Registers \\
\hline 5001942 & 500 PC & 5001 9 4 2. & \( \square \mathrm{PC} \) \\
\hline 5015943 & & 3015943 & AC \\
\hline 5022943 & 1942 R & 5022943 & \( \mathbb{R} \) \\
\hline & 1 & & 2 \\
\hline Memory & CPU Registers & Memory & CPU Registers \\
\hline \multirow[t]{3}{*}{\[
\begin{array}{l}
5001942 \\
501594+3 \\
5029.43
\end{array}
\]} & \multirow[t]{3}{*}{} & \multirow[t]{2}{*}{} & \multirow[t]{2}{*}{\( \square \mathrm{PC} \) PC} \\
\hline & & & \\
\hline & & & \\
\hline \[
942 \begin{array}{llll}
0 & 0 & 0 & 5 \\
943 \\
\hline 0 & 0 & 0 & 2
\end{array}
\] & 3 & & 4 \\
\hline Memory & \multirow[t]{2}{*}{CPU Registers
\( \square \) PC} & Memory & \multirow[t]{2}{*}{\begin{tabular}{l}
CPU Registers \\
\( \square \mathrm{PC} \)
\end{tabular}} \\
\hline \[
5 0 0 \longdiv { 1 9 + 2 }
\] & & 50019 1 9 & \\
\hline 50159 5 43 & & 5015 & AC \\
\hline 5022943 & & \( 5 0 2 \longdiv { 2 9 4 3 } \) & R \\
\hline 94300042 & 5 & 943 & 6 \\
\hline
\end{tabular}

What do the following contain?
In step 2:
Program Counter: PC in step 2 = \( \square \)
Accumulator: AC in step 2 - \( \square \)
In satep 6:
Program Counter: PC in step \( 6= \) \( \square \)
Accumulator: \( A C \) in step \( 6= \) \( \square \)
Instruction Register: IR in step 6 = \( \square \)
Location \( 942= \) \( \square \)
Location 943 = \( \square \)

Partial list of opcodes:
0001 - Load AC from memory
0010 = Store AC to memory
0101 - Add to AC from memory
Partial program execution is as illustrated:

Meanory CPU Registers Menory CPU Registers

5001942 500 PC 5001 9 4 2. □PC

5015943 3015943 AC

5022943 1942 R 5022943 ℝ

1 2

Memory CPU Registers Memory CPU Registers

[t]3*
5001942

501594+3

5029.43
[t]3* [t]2* [t]2*□PC PC

942
0 0 0 5

943
0 0 0 2
3 4

Memory [t]2*CPU Registers
□ PC Memory [t]2*
CPU Registers

□PC

5 0 0 1 9 + 2
50019 1 9

50159 5 43 5015 AC

5022943 5 0 2 2 9 4 3 R

94300042 5 943 6

What do the following contain?
In step 2:
Program Counter: PC in step 2 = □
Accumulator: AC in step 2 - □
In satep 6:
Program Counter: PC in step 6= □
Accumulator: A C in step 6= □
Instruction Register: IR in step 6 = □
Location 942= □
Location 943 = □

Added by Claudia R.

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