00:01
For the given problem, we are provided with the graph here.
00:06
On horizontal axis, we have x -axis in meters.
00:09
On vertical axis, we have a force in a newton's.
00:12
This is fx force.
00:14
The graph is in the following way.
00:18
Goes up and then goes straight and then comes down.
00:22
The maximum here is a 3, and the maximum up here is 16.
00:28
Starts from a 0 to 4 .6.
00:34
6, 8, 10, 12, 14, then 16.
00:42
So we are asked to find what will be the work for different intervals.
00:48
For a part a, we are asked to find what will be the work for the interval from x is equal to 0 to x is equal to 4.
00:57
We know that work done is equal to force times the displacement x.
01:04
We can read the force from the graph, and then x from the graph.
01:08
And then find the work or we can just say that the area under this graph graph will be the total work done so if you want to find the area if you want to find the work done somewhere here we'll find the area of this triangle then if you want to find that work done under this curve here we'll find the area of this rectangle and then if you want to find the area.
01:44
Here we will find the area of this...