00:01
It is given that a particle of mass m and charge q has an initial speed v at point a and moves to point b.
00:13
So here at point a the particle has mass m, charge q and velocity v.
00:20
Now it moves to a point b where the electric potential is v greater than at point a.
00:30
So here vb is greater than va.
00:36
Not that the potential is denoted by capital v and the velocity is denoted by small little v.
00:44
Now at point a, the kinetic energy is given by half mv square.
00:56
Let the electric potential at point a is zero.
00:59
So we have potential energy at point a is zero.
01:05
Or we can write it as b a equals 0 therefore the electric potential energy at point a p -e -a is equals to q b a where v a is zero so this is equal to 0 now at point b so this is at point a now at point b the point b the the kinetic energy at point b is served, sorry, the kinetic energy at point b, we denoted as k -e -b...