Question

A particle possessing q = 8.25 ?C of charge and a mass of m = 8.55 g is fired at a speed of v = 459 cm/s between two horizontal charged plates of length L = 34.6 cm. L y Assume that the electric field between the plates is uniform and has a constant value of E = 2030 N/C, directed upwards. Calculate the distance y by which the charge falls below a straight-line path when it reaches the end of the plates. Assume a gravitational acceleration of g = 9.81m/s². y = cm What field strength will allow the particle to pass between the plates along a straight path? field strength: N/C

          A particle possessing q = 8.25 ?C of charge and a mass of m = 8.55 g is fired at a speed of v = 459 cm/s between two horizontal charged plates of length L = 34.6 cm.
L
y
Assume that the electric field between the plates is uniform and has a constant value of E = 2030 N/C, directed upwards. Calculate the distance y by which the charge falls below a straight-line path when it reaches the end of the plates. Assume a gravitational acceleration of g = 9.81m/s².
y = cm
What field strength will allow the particle to pass between the plates along a straight path?
field strength: N/C

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A particle possessing q = 8.25 ?C of charge and a mass of m = 8.55 g is fired at a speed of v = 459 cm/s between two horizontal charged plates of length L = 34.6 cm.
L
y
Assume that the electric field between the plates is uniform and has a constant value of E = 2030 N/C, directed upwards. Calculate the distance y by which the charge falls below a straight-line path when it reaches the end of the plates. Assume a gravitational acceleration of g = 9.81m/s².
y = cm
What field strength will allow the particle to pass between the plates along a straight path?
field strength: N/C

Added by Barbara S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

09/08/2022

Step 1

Given: q = 8.25 pC = 8.25 x 10^-12 C m = 8.55 g = 8.55 x 10^-3 kg v = 459 cm/s = 4.59 m/s L = 34.6 cm = 0.346 m E = 2030 N/C g = 9.81 m/s^2 Vertical displacement y can be calculated using the equation: y = (1/2)gt^2 + vyt - (1/2)qEL^2/m Show more…

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A particle possessing q = 8.25 μC of charge and a mass of m = 8.55 g is fired at a speed of v = 459 cm/s between two horizontal charged plates of length L = 34.6 cm. Assume that the electric field between the plates is uniform and has a constant value of E = 2030 N/C, directed upwards. Calculate the distance y by which the charge falls below a straight-line path when it reaches the end of the plates. Assume a gravitational acceleration of g = 9.81m/s². What field strength will allow the particle to pass between the plates along a straight path? field strength: N/C

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