00:01
Okay, so we have a few different parts here.
00:03
One thing we know that the distribution of weights has a normal distribution with a mean of 40 and a certain deviation of 2.
00:11
And we're supposed to describe the sampling distribution when we have an equal 16.
00:15
So since this is a normal distribution, we know automatically that the sampling distribution will also be normal.
00:23
So the sampling distribution will also be exactly normal.
00:28
It'll have the same mean as the population.
00:32
And it's serend deviation of the sampling distribution is going to be sigma over the square root of n, which is 2 over 4, which is 100.
00:44
That's always going to be the case where if you have a normal population, then no matter what the sample sizes, you know that the sampling distribution is going to be normal as well.
00:52
Okay, next thing is we have a mean that we think is 1 ,000 with a certain deviation of 25, and the janus, she records the lack of times of 100 batteries and finds that the mean of those 100 batteries is 980 and asks what to do about the claim.
01:12
So we need to just find a z really quickly.
01:14
So that's going to be z equals x bar minus mu over sigma over the square of n and see how unusual the sample that is.
01:23
So we'll take 980 minus 1 ,000 divided by 25 over the square of 100.
01:31
So that's going to be negative 20 over 25 divided by 10, which is 2 .5.
01:39
If we take negative 20 divided by 2 .5, we get negative 8.
01:48
Okay, so we have a few different parts here.
01:51
One thing we know that the distribution of weights has a normal distribution with a mean of 40 and a certain deviation of 2.
01:59
And we're supposed to describe the sampling.
02:00
So that's a very large test statistic.
02:05
So i'm going to go with c.
02:07
The claim is unreasonable.
02:10
Either the true mean is less than 1 ,000, which is what this says here, right? or it could also be that the serenade deviation is larger than 25 hours.
02:18
Because if the serend deviation was much larger, say like 100, then we would have a test statistic of negative 20 over 10, right, which would be much, much smaller.
02:30
So we're going to say c for that one.
02:34
Okay.
02:35
Next we have a normal distribution with a mean of 75 ,000 and certain deviation of 10 ,000.
02:42
And four teachers are selected at random.
02:47
We want the probability that their average seller is less than $65 ,000.
02:54
Okay, so we're going to, once again, take a z test statistic...