00:01
In this particular video, we're going to discuss the design question.
00:04
The question given here is, given reaction is bb plus bb -o2, lead oxide, plus 2h positive, plus 2h -so, and products are here, 2b, so4, plus 2h -2o.
00:35
So here, this is solid, this is solid, this is a plus form.
00:42
And this is in aqueous form and this is also in aqueous form and this is in liquid state so first we will assign oxidation state on each element in a given reaction on both side of this given reaction reactantin product site so this is slid bb it is exist here in free state so according to rule to assign oxidation state on each element in a given chemical so free element always has zero oxidation state and this is a neutral compound having no charge so the sum of oxidation state of neutral compound is equal to zero so it has oxidation state minus two it is plus two so here is two subscribes so this will multiply this two into this oxidation state this will be minus four and it will as a plus four oxidation state is equal to to 0 and next here is this is one oxidation state charge charge in a charge form and here it has remaining charge minus so this is a polyatomic molecule we can say radical polyatomic radical so it has the sum of oxidation state on each element will be equal to the remaining charge so it has minus eight oxidation state oxygen has and four into two is equal to eight and sulfur has plus 6 oxidation state and hydrogen has plus 1 oxidation state.
02:18
6 plus 1, 7 plus 7 minus 7 is equal to minus 1 is equal to remaining charge.
02:26
And here in product side we have this is minus 8 plus 6 plus 2...