Question

Pb2+ + 2 e- → Pb (s) ξo = -0.13 V Ag+ + 1 e- → Ag (s) ξo = 0.80 V What is the voltage, at 298 K, of this voltaic cell starting with the following non-standard concentrations: [Pb2+] (aq) = 0.093 M [Ag+] (aq) = 0.93 M Use the Nernst equation: ξ = ξo - (RT/nF) ln Q First, calculate the value of Q and enter it into the first answer box. Q is dimensionless.

Name: pb2 2 e pb s o 013 v ag 1 e ag s o 080 v what is the voltage at 298 k of this voltaic cell starting with the following non standard concentrations pb2 aq 0093 m ag aq 093 m use the nernst eq 96082
Uploaded: 2023-05-11T23:00:34-08:00
Duration: 2 min 46 s
Channel: David Collins
Description: pb2 2 e pb s o 013 v ag 1 e ag s o 080 v what is the voltage at 298 k of this voltaic cell starting with the following non standard concentrations pb2 aq 0093 m ag aq 093 m use the nernst eq 96082

          Pb2+ + 2 e- → Pb (s)
ξo = -0.13 V

Ag+ + 1 e- → Ag (s)
ξo = 0.80 V

What is the voltage, at 298 K, of this voltaic cell starting with the following non-standard concentrations:

[Pb2+] (aq) = 0.093 M
[Ag+] (aq) = 0.93 M

Use the Nernst equation:

ξ = ξo - (RT/nF) ln Q

First, calculate the value of Q and enter it into the first answer box. Q is dimensionless.

Added by Kristin W.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

05/11/2023

Step 1

The balanced redox reaction is: $$Pb^{2+} + 2Ag \rightarrow Pb + 2Ag^+$$ Show more…

Show all steps

Thanks for your feedback!

Pb2+ + 2 e- → Pb (s) ξo = -0.13 V Ag+ + 1 e- → Ag (s) ξo = 0.80 V What is the voltage, at 298 K, of this voltaic cell starting with the following non-standard concentrations: [Pb2+] (aq) = 0.093 M [Ag+] (aq) = 0.93 M Use the Nernst equation: ξ = ξo - (RT/nF) ln Q First, calculate the value of Q and enter it into the first answer box. Q is dimensionless.