00:01
For this question, you are being told pc world provided ratings for the top five small office laser printers and five corporate printers.
00:10
The highest rating small office laser printer was the minorita qms page pro 250, 1000250 with an overall rating of 91.
00:23
The highest rated corporate laser printer, the xerox phaser 440 slash n, with an overall rating of 83.
00:34
The following data show the speed of the plain text printing in pages per minute and the price of each printer.
00:42
Develop the estimated regression equation with speeds as the independent variable.
00:50
Okay, so let's come to the first part.
00:56
Okay, so for this question we'll have to calculate the slope, the intercept for the estimated regression equation.
01:05
Okay, so from our data given to us, let us call the speed xi, the price as yi.
01:16
Then let us do xi minus the mean of x and yi minus the mean of x and yi minus the mean.
01:27
Of y and then we'll have these two values multiplied with each other okay let me just bring this more to the left as we need more space and the final column we'll have x i minus mean of x whole square okay let me just arrange this neatly okay now let's start with listing our values so first we'll reach all the values of x i which is ideally considered to be the speed okay let me start listing them for you it is 12 10 12 .2 10 .10 10 .3 11 .7 17 .7 17 .8 16 .1 1 .11 .8 19 .8 28 28.
02:34
28.
02:36
2 and 149 .9.
02:40
Now let's just the buy of five which is the price.
02:44
The prices are one ninety nine four ninety nine two ninety nine two ninety nine again three ninety nine one eight five zero one thousand one three eight seven two zero eight seven two zero eight nine two 2 -200 -149 this is equal these are the totals by the way 1 -0 -2 -1 this is where our data set ends and here i'm just summarizing the totals okay so now x minus the mean that will be the mean for x is 4099 and 12 minus 1499 would be minus 1499 would be minus 2 .99 minus 2 .99 minus 4 .9 999 minus 2 .79 minus 4 .69 minus 3 .29 .2 .82 .81.
03:54
1 .1 .1 .1 .4 .81.
04:01
13 .13 .13 .1.
04:02
Okay.
04:03
Now, the y minus the mean of y.
04:06
The mean of y is 1 ,022.
04:08
2 .1 so from all the values of y will minus 1202 .1 okay the values of minus 8 to 3 .10 minus 5 to 3 .10 minus 7 to 3 .10 minus 7 to 3 .10 minus 7 to 3 .10 minus 6 to 3 .10 minus 6 to 3 .10 8 to 7...