00:01
On this question, basically, you apply the sni's law, right, to find the ratio first, right? so you have the diameter of the glass and you have the hatch of the glass, right? as you're in this diagram.
00:13
So when you don't feel any liquid, you would see just this point.
00:17
If you put your eye here, while if you fear the liquid, you would actually see the center.
00:20
Now, if you think about this, you would have seen something like this.
00:26
Now, the light is going up and it's going to refract it, right? and obviously, if you think about this, the way going like this, so there will be angle here, right? so that's, that's theta, i'll call it theta i, okay? and this reflected angle, which is somewhere here, that would be theta arrow, right? and you know that cita, sine cita i equals the reflective index n times sine ceta r, right? now, what is cincidei? well, sensitive i, you can actually work out from the first.
01:00
Diagram here.
01:01
San cciti -i because you think about this is cd -i there what this is all cita -i right so santa c -ti actually is given by just the d right the distance d divided by this lens here what's that that's square root of d squared plus h squared right that's santa i and how about uh so that's sine cedar i is given by this another sensor order well cccdata a lot and it's given by only half there so sensitive r will be given by half d, right, and divided by this side, right, of this triangle, which is going by d over half squared plus h squared, right? now if you are plugging those into this equation, and i would like to actually also square this equation, then you would find d squared over d squared, plus h squared equals n squared and times d squared over four.
02:08
So i put four here maybe and divided by d squared plus four h squared, right? that would be what you find...