pH = -log[H?O?] pOH = -log[OH?] pH + pOH = 14 K? = [H?O?][OH?] K? = 1.0 × 10?¹? 3. For each reaction below, label each reactant as acid or base, label each product as conjugate acid or conjugate base and list the two conjugate acid-base pairs: PLAN: The acid donates a proton (H?) to form its conjugate base; the base accepts a proton to form its conjugate acid. Every acid has a conjugate base, and every base has a conjugate acid. The acid has one more H and one more positive charge than its conjugate base. A. HBr(aq) + HS?(aq) ? H?S(aq) + Br?(aq) B. HClO(aq) + CH?NH?(aq) ? CH?NH??(aq) + ClO?(aq) 4. Give the conjugate bases of the following acids: PLAN: Remove H? from each acid to get the conjugate base: the charge becomes more negative since you are removing a +1 charge. The charge of the species is important, so don't omit it! a. HNO? b. HPO?²? c. HCOOH
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pH = -log[H+] This equation tells us that the pH of a solution is equal to the negative logarithm of the concentration of hydrogen ions ([H+]) in that solution. Show more…
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If a solution has a pOH of 4.73, what is the solution's [H+] concentration? pOH = -log [OH-] pH = -log [H+] 14 = pH + pOH 1 x 10^14 M^2 = [H+] [OH-] 9.27 5.37 x 10^10 M 5.37 x 10^-10 M 186 x 10^-5 M
Sima S.
[H+][OH-] = Kw [H3O+] = 10^-pH [OH-] = 10^-pOH pH = -log[H+] pOH = -log[OH-] pH + pOH = pKw pH [H+] pOH [OH-] Acid, Base or Neutral Kw pKw 4 10 0.01 0.1 7 7 8 6 0.03 0.00038 6.5 x 10^-6 9.28 12.29 neutral 2.3 x 10^-7 0.00004
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