Pharmaceutical companies promote their prescription drugs using television advertising. In a survey of 100 randomly sampled television viewers, 15 indicated that they asked their physician about using a prescription drug they saw advertised on TV.What is the margin of error for a 90% confidence interval estimate? Note: Round "z-scores" and round your final answer to 2 decimal places.
Added by Ashley K.
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- In the survey, 15 out of 100 viewers asked their physician about a prescription drug they saw advertised. - Therefore, the sample proportion (p̂) is calculated as: \[ p̂ = \frac{15}{100} = 0.15 \] Show more…
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