00:01
To consider the equation i've written here.
00:03
And we're given 22 .7 grams of pbo, and we're going to react that with 17 .8 grams of nacl.
00:31
And we are given an actual yield is 20 .7 grams of fosgenite.
00:50
Let's see if i'm spelling that right, fosgenite.
00:59
We're asked to find theory.
01:02
Theoretical yield and percent yield.
01:16
Okay, let's do it.
01:18
I'm using one of my least favorite pens because my other one is dead, so i apologize in advance.
01:30
So i'm going to convert this to fosgenite and let me get the molar mass of fosgenite which we said was pb2, pb2, cl2, co3, and the thick gets me here.
02:07
Pb2 sealed.
02:09
It would be 545 .31.
02:14
Oopsy.
02:17
That's the wrong one.
02:27
That seems wrong.
02:30
No, it doesn't.
02:31
That seems good.
02:33
And pbo is 223 .2.
03:07
Then i'm going to have a 2 to 1 mole ratio.
03:17
And i'm just going to call this p with quotation marks around it, so i don't have to write that out.
03:33
And we said that was 545 .31 grams of p for mole of p.
03:51
Let me see how many grams that would be.
03:58
Times 5 .45 .31 divided by 223 .2.
04:07
Is, oopsie, i did that wrong, 22 .7.
04:12
Times 545 .31 divide 223 .2.
04:20
And that will be 27 .7 grams of fosgenite.
04:33
Now let's do the same calculation with the sodium chloride.
04:41
Sodium chloride is about 58 .5, 58 .44 and i've got a 2 to 1 mole ratio again...