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QUESTION 5 Railway carriage X, of mass 21 000 kg, crashes into the back of railway carriage Y which is travelling in the same direction as X on a straight level track. The graph shows how the velocity of each railway carriage varies with time velocity (m.s?) 5 X 4 3 Y 2 X 1 Y 0 1,0 2,4 time (s) Ignore frictional forces between the railway carriages and the track during the collision. Ignore air resistance. 5.1 Define the term Impulse in words. (2) 5.2 Calculate the magnitude of the impulse railway carriage X experiences between 1,0 s and 2,4 s. (3) 5.3 Calculate the magnitude of the force that railway carriage X exerts on carriage Y between 1,0 s and 2,4 s. (3) 5.4 What is the magnitude of the force that carriage Y exerts on carriage X? Explain using principles of physics. (3) 5.5 State principle of conservation of momentum, in words (2) 5.6. Calculate the mass of railway carriage Y. (4) [17]

          QUESTION 5
Railway carriage X, of mass 21 000 kg, crashes into the back of railway carriage Y
which is travelling in the same direction as X on a straight level track. The graph
shows how the velocity of each railway carriage varies with time
velocity (m.s?)
5 X
4
3 Y
2 X
1 Y
0 1,0 2,4 time (s)
Ignore frictional forces between the railway carriages and the track during the
collision. Ignore air resistance.
5.1 Define the term Impulse in words. (2)
5.2 Calculate the magnitude of the impulse railway carriage X experiences between 1,0 s and 2,4 s. (3)
5.3 Calculate the magnitude of the force that railway carriage X exerts on carriage Y between 1,0 s and 2,4 s. (3)
5.4 What is the magnitude of the force that carriage Y exerts on carriage X? Explain using principles of physics. (3)
5.5 State principle of conservation of momentum, in words (2)
5.6. Calculate the mass of railway carriage Y. (4)
[17]

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QUESTION 5
Railway carriage X, of mass 21 000 kg, crashes into the back of railway carriage Y
which is travelling in the same direction as X on a straight level track. The graph
shows how the velocity of each railway carriage varies with time
velocity (m.s?)
5 X
4
3 Y
2 X
1 Y
0 1,0 2,4 time (s)
Ignore frictional forces between the railway carriages and the track during the
collision. Ignore air resistance.
5.1 Define the term Impulse in words. (2)
5.2 Calculate the magnitude of the impulse railway carriage X experiences between 1,0 s and 2,4 s. (3)
5.3 Calculate the magnitude of the force that railway carriage X exerts on carriage Y between 1,0 s and 2,4 s. (3)
5.4 What is the magnitude of the force that carriage Y exerts on carriage X? Explain using principles of physics. (3)
5.5 State principle of conservation of momentum, in words (2)
5.6. Calculate the mass of railway carriage Y. (4)
[17]

Added by Wendy B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Vishal Gupta

03/20/2025

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### 5.1 Define the term Impulse in words. ** Show more…

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QUESTION 5 Railway carriage X, of mass 21 000 kg, crashes into the back of railway carriage Y which is travelling in the same direction as X on a straight level track. The graph shows how the velocity of each railway carriage varies with time Ignore frictional forces between the railway carriages and the track during the collision. Ignore air resistance. 5.1 Define the term Impulse in words. 5.2 Calculate the magnitude of the impulse railway carriage X experiences between 1,0 s and 2,4 s. 5.3 Calculate the magnitude of the force that railway carriage X exerts on carriage Y between 1,0 s and 2,4 s. 5.4 What is the magnitude of the force that carriage Y exerts on carriage X? Explain using principles of physics. 5.5 State principle of conservation of momentum, in words 5.6. Calculate the mass of railway carriage Y.

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00:01 Hi, here in this given problem, mass of the railway carriage x, let it be represented as mx.

00:09 This is given to be equal to 21 ,000 kilograms.

00:14 In the first part of the problem 5 .1, we have to define the term impulse, inverse.

00:23 An impulse, it may be defined as, either it is defined as the product of force applied on an object, and the time duration for which it is applied.

01:07 And then using newton's second law of motion, which says the force acting on an object is equal to time rate of change of linear momentum of the object.

01:30 So making a cross multiplication, we can say the product of force and time duration fdt, that is equal to change in momentum.

01:36 So impulse acting on an object may also be defined as the changing linear momentum in that object.

02:10 Now in the next part 5 .2, we have to calculate the magnitude of impulse, railway carriage x experience between time 1 .02, 2 .4 second i .x.

02:27 And that will be given by the product of means we will find it by.

02:32 The change in momentum means mx multiplied by change in velocity its final velocity that is 2 meter per second initially it was 5 meter per second so that is 2 minus 5 means this is 21 000 multiplied by minus 3 so i x impulse received by the carriage x that is minus 63 000 kilograms meter per second.

03:05 Answer for the second part and this is 5 .2 not part b.

03:11 This is maybe this should be represented as 5 .2.

03:15 Now 5 .3...

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