A fast elevator in a skyscraper is employing the following scheme to get from the starting level to the desired level: For the first half of the time it accelerates at the maximum allowed acceleration of 1.0 m/s^2 and for the second half it decelerates at the maximum allowed acceleration of -1.0 m/s^2. How long does it take (in seconds) to go from ground level to the highest level at 80 m elevation?
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Step 1: Calculate the displacement in the first half of the time: \(S_1 = \frac{1}{2} \times (1) \times (\frac{t}{2})^2 = \frac{t^2}{8}\) Show more…
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