00:01
So let us start with the concept which we are going to use here for this question.
00:08
So according to relativity, the delta t, this should be equals to the t one half divided by the relativity factor that is under root over one minus v square by c square, where v is the speed in medium, c is speed in vacuum and t one half is the half -life of the given radioactive material.
00:30
So according to given for the p on the t one half, we have been given 1 .8 into 10 to the power minus of 8 seconds and the medium velocity we have been given 0 .8 times of c.
00:46
So first of all let us calculate the distance traveled, a distance traveled by the p on, so this can be calculated as these equals to the velocity times of t will be goes to 4 .32 meters.
01:06
Now by using the relativity factor formula, let us find delta t.
01:11
So this can be equals to t one half divided by under root over relativity factor one minus v square by c square.
01:18
So this will be goes to t one half is 1 .8 into 10 to the power minus of 8 divided by the under root over one minus of v is 0 .8 times of c divided by this c, that whole square where cc get cancel.
01:35
This will be goes to 1 .8 into 10 to the power minus of 8 divided by under root over one minus 0 .8 whole square will become 0 .64...