Question

Place the following compounds in order of decreasing strength of intermolecular forces resulting to a decrease in the melting and boiling points. I. CH$_3$-CH(OH)-CH$_2$-CH$_3$ II. CH$_3$CH$_2$CH$_2$CH$_2$CH$_3$ III. CH$_3$-CH$_3$-CO-CH$_3$

Name: place the following compounds in order of decreasing strength of intermolecular forces resulting to a decrease in the melting and boiling points i ch3 choh ch2 ch3 ii ch3ch2ch2ch2ch3 66212
Uploaded: 2024-05-15T06:51:22-08:00
Duration: 3 min 24 s
Channel: Adi S
Description: place the following compounds in order of decreasing strength of intermolecular forces resulting to a decrease in the melting and boiling points i ch3 choh ch2 ch3 ii ch3ch2ch2ch2ch3 66212

          Place the following compounds in order of decreasing strength of intermolecular forces resulting to a decrease in the melting and boiling points.
I. CH$_3$-CH(OH)-CH$_2$-CH$_3$
II. CH$_3$CH$_2$CH$_2$CH$_2$CH$_3$
III. CH$_3$-CH$_3$-CO-CH$_3$

place the following compounds in order of decreasing strength of intermolecular forces resulting to a decrease in the melting and boiling points i ch3 choh ch2 ch3 ii ch3ch2ch2ch2ch3 66212

Added by James A.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

05/15/2024

Step 1

Compound I, CH$_3$-CH(OH)-CH$_2$-CH$_3$, contains a hydroxyl group (-OH), which can form hydrogen bonds, the strongest type of intermolecular force. Compound II, CH$_3$CH$_2$CH$_2$CH$_2$CH$_3$, is a nonpolar alkane. It only exhibits weak London dispersion Show more…

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Place the following compounds in order of decreasing strength of intermolecular forces resulting to a decrease in the melting and boiling points. I. CH$_3$-CH(OH)-CH$_2$-CH$_3$ II. CH$_3$CH$_2$CH$_2$CH$_2$CH$_3$ III. CH$_3$-CH$_3$-CO-CH$_3$