Please anser questions abcdefg 1 a 15 cm tall object is...

1) A 1.5 cm tall object is placed 5 cm from a concave mirror of focal length 2.5 cm. a. Calculate the distance of the image from the mirror in cm. Show formulas and calculations. b. Calculate the height of the image in cm. Show formulas and calculations. c. Using a ruler and the given info, show the precise position of the object and its height on the following diagram. Complete the ray diagram to show the formation of the image. d. Using a ruler, measure the distance of the image you drew from the mirror. What is the measured distance in cm? e. Using a ruler, measure the height of the image you drew. What is the measured value for the height of the image in cm? f. How does the calculated image distance in (a) compare to the measured value of the image distance in (d)? How do you expect them to be? g. How does the calculated image height in (b) compare to the measured value of the image height in (e)? How do you expect them to be?

Transcript

00:01 Hello students here is a solution.

00:03 First of all here given that a 1 .5 cm tall object is placed at 5 cm from a concave mirror of focal length 2 .5 cm so in part a we have to find out or calculate the distance of the image from the mirror in centimeter, show formulas and calculations.

00:20 So dear students first of all here we have to find out the value of v and here you is minus 5 cm here the sign is negative and here is the concave lens and concave lens the focal length is negative so that's why here the focal length is negative so that's why here the focal length is equal length is to minus of 2 .5 centimeter.

00:33 Now we know that the solution of part a so here the solution of part a we know that the mirror formula 1 upon f is equals to 1 upon v plus 1 divided by u or 1 divided by f is equal to 1 divided by v plus 1 divided by u.

00:48 Now put all the values here so here minus 1 divided by 2 .5 is equals to 1 divided by v minus 1 divided by 5 and after solving this equation we get the value of v is equal to 5 centimeter right so here the value so here the value of is equals to minus of five centimeter here minus shows that that the image is real and inverted okay so the image distance from the mirror is five centimeter and that is the answer of part one okay or part a now moving to the part b in part b we have to calculate the height of the image in centimeter so here we have to find out the height of image and we know that the magnification is equals to minus v divided by u is equals to height of image divided by the height of object right so here the value of minus v or the value of v is equal to minus 5 divided by the value of you is also the minus 5 is equal to height of image divided by height of object which is equal to here 5 and 5 cancel v reader with each other which equals to minus 1 so here the height of image is equal to minus 1 multiply by height of object so here height of image is equal to minus 1 multiply by height of objector so here height of image is equal to minus 1.

02:03 Multiply by 1 .5 cm so here the height of image is equal to minus 1 .5 centimeter and here negative sign again shows that it is a real and inverted image.

02:14 So if we are talking about the height which is equal to 1 .5 centimeter which is equals to the height of object so both are the same...

Question

Please give Ace some feedback