00:01
We compute for the average flow rate as the product of the cross -sectional area through which the fluid passes or flows through and multiplied by its average speed.
00:14
So here we have the flow rate.
00:19
If this is expressed in cubic meter per second, your a, which is the area, has to be in meter squared, and your v, which is the velocity or speed, has to be in meters per second.
00:34
We're given with the flow rate, which is 3 .6 times 10 to the negative 6, the cross -section of the artery that has a diameter of 7 .8 millimeter, and we want to find the average speed.
00:50
So we first write the equation to solve for the v as v equals q over a, where again your q is equal to 3 .6 times 10 to the negative 6.
01:06
Now your area is not the diameter yet, but we have to solve for the area, assuming that the cross -section is circular, which means that we are going to solve the area using the area of the circle, which is in terms of diameter, is solved as pi over 4 d squared, where d is the diameter, and since we want this to be meter squared, we need to express your d diameter in terms of meters.
01:32
So we note that 7 .8 millimeter is also means that we have to convert it, so 1000 millimeter is 1 meter.
01:46
So therefore, we need to divide 7 .8 by 1000, that gives you 0 .0078, and then v squared...