You randomly select and measure the contents of 10 bottles of cough 4.216 4.291 4.254 4.244 4.187 syrup. The results (in fluid ounces) are shown to the right. 4.269 4.262 4.249 4.227 4.232 Assume the sample is taken from a normally distributed population. Construct 99% confidence intervals for (a) the population variance $\sigma^2$ and (b) the population standard deviation $\sigma$. Interpret the results.
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You randomly select and measure the contents of 10 bottles of cough syrup. The results (in fluid ounces) are shown to the right: 4.212 4.297 4.254 4.242 4.182 4.204 4.265 4.241 4.229 4.237 Assume the sample is taken from a normally distributed population. Construct 99% confidence intervals for (a) the population variance σ² and (b) the population standard deviation σ. Interpret the results. (a) The confidence interval for the population variance is ( , ). (Round to six decimal places as needed.)
James K.
Assume the sample is from a normally distributed population and construct the indicated confidence intervals for $(a)$ the population variance $\sigma^{2}$ and $(b)$ the population standard deviation $\sigma .$ Interpret the results. Cough Syrup The volumes (in fluid ounces) of the contents of 15 randomly selected bottles of cough syrup are listed. Use a $90 \%$ level of confidence. $\begin{array}{lllll}4.211 & 4.246 & 4.269 & 4.241 & 4.260 \\ 4.293 & 4.189 & 4.248 & 4.220 & 4.239 \\ 4.253 & 4.209 & 4.300 & 4.256 & 4.290\end{array}$
Confidence Intervals
Confidence Intervals for Variance and Standard Deviation
A random sample of 100 12 oz ketchup bottles is taken. a) If the mean and standard deviation of these 100 values were 12.02 and 0.01, respectively, with what confidence can we assert that 12.02 oz is within 0.001 of the true mean amount of ketchup in a 12 oz bottle? b) If the bottles yielded a standard deviation of 0.1 oz, what is a 99% confidence interval for the standard deviation of the amount of ketchup in a 12 oz bottle? Show work, please.
Adi S.
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