Question

1 Inverse Laplace Transform Determine the time domain function that correspond with the following Laplace Transform. 1. $Y(s) = s^4X(s) + e^{-6s}X(s) + \frac{dY(s)}{ds}$ (Your answer should be a differential equation.) 2. $H(s) = \frac{120}{s(s+1)(s+2)}$ 3. $H(s) = \frac{10}{s(s+2)^2}$

          1 Inverse Laplace Transform
Determine the time domain function that correspond with the following
Laplace Transform.
1. $Y(s) = s^4X(s) + e^{-6s}X(s) + \frac{dY(s)}{ds}$
(Your answer should be a differential equation.)
2. $H(s) = \frac{120}{s(s+1)(s+2)}$
3. $H(s) = \frac{10}{s(s+2)^2}$

1 Inverse Laplace Transform
Determine the time domain function that correspond with the following
Laplace Transform.
1. Y(s) = s^4X(s) + e^-6sX(s) + (dY(s))/(ds)
(Your answer should be a differential equation.)
2. H(s) = (120)/(s(s+1)(s+2))
3. H(s) = (10)/(s(s+2)^2)

Added by Susan M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adriano Chikande

Step 1

H(s) = 120/(s+2) To find the inverse Laplace transform of H(s), we need to express it in a form that matches a known transform pair. In this case, H(s) is in the form of a constant divided by a linear term (s+2). The inverse Laplace transform of 1/(s+a) is Show more…

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Inverse Laplace Transform Determine the time domain function that corresponds with the following Laplace Transform. (Your answer should be a differential equation.) 1. H(s) = 120/(s+2) 2. H(s) = 10s/(s+2)^2