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Please answer the following questions, thank you An object is undergoing simple harmonic motion along the x-axis. Its position is described as a function of time by x(t) = 1.4 cos(3.8t – 1.6), where x is in meters, the time, t, is in seconds, and the argument of the cosine is in radians. a) Calculate the object’s acceleration, in meters per second squared, at time t = 0. b) What is the magnitude of the object’s maximum acceleration, in meters per second squared?

          Please answer the following questions, thank you
 An object is undergoing simple harmonic motion along the x-axis. Its position is described as a function of time by x(t) = 1.4 cos(3.8t – 1.6), where x is in meters, the time, t, is in seconds, and the argument of the cosine is in radians. 
a) Calculate the object’s acceleration, in meters per second squared, at time t = 0. 
b)  What is the magnitude of the object’s maximum acceleration, in meters per second squared?
        
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Added by Lee C.

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Please answer the following questions, thank you An object is undergoing simple harmonic motion along the x-axis. Its position is described as a function of time by x(t) = 1.4 cos(3.8t – 1.6), where x is in meters, the time, t, is in seconds, and the argument of the cosine is in radians. a) Calculate the object’s acceleration, in meters per second squared, at time t = 0. b) What is the magnitude of the object’s maximum acceleration, in meters per second squared?
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Transcript

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00:01 All right, so we have a particle undergoing simple harmonic motion, and we're told the position as a function of time is given by 5 .3 times the cosine of 4 .2 t minus 1 .9.
00:16 So 4 .2, presumably this is like radiance per second, times t plus, so plus or minus, minus 1 .9 radiance.
00:29 And the amplitude, sorry, is in meters.
00:33 So this should be 5 .3 meters.
00:36 So this is our position as a function of time.
00:39 And we want to know what is the position of the object at 2 .6 seconds.
00:44 So let's just plug this in.
00:48 This would be 5 .3 meters times the cosine of 4 .2 radians per second times 2 .6 seconds minus 1 .9 radiance.
01:06 So if you're doing this along with me in your calculator, make sure your calculators in radiance rather than degrees.
01:12 So we got 4 .2 times 2 .6 minus 1 .9.
01:17 Take the cosine of that, multiplied by 5 .3.
01:20 You should get something like negative 4 .87 meters.
01:26 And then we also want to know what is the velocity and basically the acceleration at the same time.
01:33 So the velocity as a function of time is just going to be negative 5 .3 meters times 4 .2 radiance a second times the sign of the same argument.
01:49 So 4 .2 radians a second times 2 .6 seconds minus 1 .9 radians.
02:00 So if we do that, 4 .2 times 2 .6 minus 1 .9, and we take the sign of that, and then multiply by 5 .3 times 4 .2...
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