Question

Problem 5.2 $v_0$ $\theta$ 1.2 m A ball is thrown with an initial velocity which has magnitude $v_0 = 15 m/s$ and an angle of elevation $\theta = 60^\circ$. The gravity force acting on the ball. The ball has a mass of 0.2 kg. Find $v_x(t)$, $v_y(t)$ and trajectory $y(x)$ of the ball the time interval $t = [0; 1]s$. Create $v_x(t)$, $v_y(t)$ and trajectory $y(x)$ graphs.

          Problem 5.2

$v_0$
$\theta$
1.2 m
A ball is thrown with an initial velocity which has magnitude $v_0 = 15 m/s$ and an angle of elevation $\theta = 60^\circ$. The gravity force acting on the ball.
The ball has a mass of 0.2 kg.
Find $v_x(t)$, $v_y(t)$ and trajectory $y(x)$ of the ball the time interval $t = [0; 1]s$.
Create $v_x(t)$, $v_y(t)$ and trajectory $y(x)$ graphs.

Problem 5.2

v0
θ
1.2 m
A ball is thrown with an initial velocity which has magnitude v0 = 15 m/s and an angle of elevation θ = 60^∘. The gravity force acting on the ball.
The ball has a mass of 0.2 kg.
Find vx(t), vy(t) and trajectory y(x) of the ball the time interval t = [0; 1]s.
Create vx(t), vy(t) and trajectory y(x) graphs.

Added by Emily T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Akancha C

Step 1

The horizontal component of the initial velocity (vx) can be found using the equation vx = vo * cos(theta), where vo is the magnitude of the initial velocity and theta is the angle of elevation. vx = 15m/s * cos(60°) vx = 15m/s * 0.5 vx = 7.5m/s The vertical Show more…

Show all steps

Thanks for your feedback!

Problem 5.2 Vo = 15m/s A ball is thrown with an initial velocity which has magnitude vo = 15m/s and an angle of elevation = 60Â°. The gravity force acting on the ball. The ball has a mass of 0.2 kg. Find vx, vy, and trajectory y-x of the ball in the time interval t = [0;1]s. Create vx-t, vy-t, and trajectory y-x graphs.