Question

Calculate the number of milliliters (mL) of ammonia whose density is 0.99 g/mL, 2.3% by weight NH3, which will be required to precipitate the iron as Fe(OH)3 in a 0.74 g sample that contains 22% FeO. Rxn: 3NH3 + Fe3+ + 3H2O → Fe(OH)3 + 3NH4+

Name: please answer with detailed information thank you calculate the number of milliliters ml of ammonia whose density is 099 gml 23 by weight nh3 which will be required to precipitate the iron a 73808
Uploaded: 2023-03-30T17:03:12-08:00
Duration: 3 min 41 s
Channel: Sri K
Description: please answer with detailed information thank you calculate the number of milliliters ml of ammonia whose density is 099 gml 23 by weight nh3 which will be required to precipitate the iron a 73808

          Calculate the number of milliliters (mL) of ammonia whose density is 0.99 g/mL, 2.3% by weight NH3, which will be required to precipitate the iron as Fe(OH)3 in a 0.74 g sample that contains 22% FeO.

Rxn: 3NH3 + Fe3+ + 3H2O → Fe(OH)3 + 3NH4+

Added by Brooke G.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

03/30/2023

Step 1

74 g sample of iron oxide: \[0.74 \, \text{g} \times 0.22 = 0.1628 \, \text{g}\] Show more…

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Calculate the number of milliliters (mL) of ammonia whose density is 0.99 g/mL, 2.3% by weight NH3, which will be required to precipitate the iron as Fe(OH)3 in a 0.74 g sample that contains 22% FeO. Rxn: 3NH3 + Fe3+ + 3H2O → Fe(OH)3 + 3NH4+