The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles are mA = 1,365 kg, mB = 1,548 kg, and mC = 1,048 kg. Find the magnitude of the net gravitational force acting on particle A. (G = 6.67 x 10-11 N.m2/kg2)
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The formula for gravitational force is: F = G * (m1 * m2) / r^2 where: - F is the gravitational force, - G is the gravitational constant (6.67 * 10^-11 N*m^2/kg^2), - m1 and m2 are the masses of the two particles, Show more…
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Sanu K.
Please show steps in detail to solve. I continue to get this question wrong.
Nishant K.
The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles are $m_{\mathrm{A}}=363 \mathrm{~kg}_{0} m_{\mathrm{B}}=517 \mathrm{~kg}_{o}$ and $m_{\mathrm{C}}=154 \mathrm{~kg} .$ Find the magnitude and direction of the net gravitational force acting on (a) particle A, (b) particle $\mathrm{B},$ and (c) particle $\mathrm{C}$.
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