Question

At time $t = 0$, a free particle in 3d ($V(x, y, z) = 0$) is in the superposition state, $\psi(\vec{r}, 0) = \frac{\pi^{-3/2}}{2L^{3/2}} \sin(3x/L)e^{i(5y+z)/L}$. (a) If the energy of the particle is measured at $t = 0$, what value is found?

          At time $t = 0$, a free particle in 3d ($V(x, y, z) = 0$) is in the superposition state,
$\psi(\vec{r}, 0) = \frac{\pi^{-3/2}}{2L^{3/2}} \sin(3x/L)e^{i(5y+z)/L}$.
(a) If the energy of the particle is measured at $t = 0$, what value is found?

At time t = 0, a free particle in 3d (V(x, y, z) = 0) is in the superposition state,
ψ(r⃗, 0) = (π^-3/2)/(2L^3/2)sin(3x/L)e^i(5y+z)/L.
(a) If the energy of the particle is measured at t = 0, what value is found?

Added by Jose Luis J.

JEE Physics

StemEZ 1st Edition

Chapter 2

Instant Answer

Solved by Expert Dave Kratz

Step 1

The particle is in a superposition state, which means it is in a combination of different energy states. The given state is √(7π/2) T0, where T0 represents the energy eigenstate. Show more…

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At time t=0, a free particle in 3D space, Vy=0, is in the superposition state âˆš(7Ï€/2) T0= a) If the energy of the particle is measured at t=0, what value is found?