The velocity of an object of mass ( m ) moving on the ( x O y ) plane is given by ( vec{v}= ) ( alpha t vec{e}_{x}+eta t^{2} vec{e}_{y} ), where ( alpha ) and ( eta ) are constants. The net force exerted on the object is given by
Added by Dji S.
Close
Step 1
We know that the velocity of the object is given by the vector function: \( \vec{v}(t) = \alpha t \vec{e}_{x} + \beta t^{2} \vec{e}_{y} \) Show more…
Show all steps
Your feedback will help us improve your experience
Timothy James and 55 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
An object with mass $m$ is moving along the $x$ -axis according to the equation $x(t)=\alpha t^{2}-2 \beta t,$ where $\alpha$ and $\beta$ are positive constants. What is the magnitude of the net force on the object at time $t=0 ?$
A mass $m$ is accelerated by a time-varying force $\alpha \exp (-\beta t) v^{3}$, where $v$ is its velocity. It also experiences a resistive force $\eta v$, where $\eta$ is a constant, owing to its motion through the air. The equation of motion of the mass is therefore $$ m \frac{d v}{d t}=\alpha \exp (-\beta t) v^{3}-\eta v $$.
An object with mass m is moving along the x-axis according to the equation x(t) = α * t^2 - 2β * t, where α and β are positive constants. What is the magnitude of the net force on the object at time t = 5s?
Adi S.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD