00:01
Hello students it is given that capacitor c1 and c2 are connected in to these where c1 is 3 microfarrid which is equal to 3 into 10 to the power minus 6 ferret c2 is equal to 4 microfarrad which is equal to 4 into 10 to the power minus 6 ferret and b is given as 1 ,000 volts so for part a, we know that since this is a series connection, so the total capacitance is equal to c1 into c2 divided by c1 plus c2, which is equal to 3 into 10 to the power minus 6 into 4 into 10 to the power minus 6 divided by 3 into 10 to the power minus 6 plus 4 into 10 to the power minus 6, which gives that the net capacitance.
01:01
Is equal to 1 .7 1 into 10 to the power minus 6 fared.
01:12
Now in series connection q1 is equal to q2 is equal to q net so q net is equal to that is the total charge is equal to the total capacitance that is c net into b which is equal to 1 .71 into 10 to the power minus 6 into 1 ,000 which comes out to be that q net is equal to 1 .71 into 10 to the power minus 3 coulum.
01:58
Let's solve part b.
02:05
We know that v1 is equal to q1 divided by c1.
02:12
Q1, q2, both are equal to this.
02:15
So we have 1 .71 into 10 to the power minus 3 divided by c1, that is 3 into 10 to the power minus 6, which gives v1 is equal to 56 .6 volts and v2 is equal to q2 divided by c2 which is equal to 1 .71 into 10 to the power minus 3 divided by 4 into 10 to the power minus 6 which comes out to be 4...