00:01
Okay, so this is basically about calculating the ph of the buffer solution.
00:06
So remember, the ph of the buffer solution equals to what? equals to the pca of the conjugate acid, minus the log the concentration of the conjugate asset over the concentration of the conjugate base.
00:26
If they are in the same solution, that means we can re -reliquate.
00:31
Right the equation, it becomes pk minus the mores of the conjugate acid over the mores of the conjugate base.
00:42
So here it tells you the k -a, right? the p -k is minus log k -a and minus log.
00:51
So the mores of the h -a is 0 .6.
00:55
And the mores of the a minus is also 0 .6.
01:00
So that's equal to minus log.
01:03
The k here is 7 .41 times 10 to minus 4...