00:01
This version we are assigned to the task to write the iopic name of the given compound including the stereochemistry.
00:15
The given compound is shown as identify the longest continuous carbon chain in this case that is 1, 2, 3, 4, 5.
00:31
The longest continuous carbon chain contains 5 carbon atoms and only single cc bonds are present in the compound.
00:45
Therefore, it is named as pentane.
00:49
There is no any functional group is present in this case.
00:53
Therefore, the name remains same as pentane.
00:57
Now identify the substituents present.
01:02
In this case, there is a bromogro group at second carbon atom and a bromogro group at third carbon atom.
01:11
Therefore, it is named as 2 -3 dibromo -pentine.
01:21
Now we have to see the stereochemistry in this compound...