00:01
In this question we need to identify the reaction where the product is formed as for the anti -marconikov's rule.
00:06
So to start with the explanation, let me explain first of all what is the marconikov's rule, right? let me first explain what is the marconikov's rule and anti -marconikov's rule is going to be just reversed to that.
00:20
So this rule applies for the alkymes of this particular form.
00:25
Why this particular form? because in this form, there are two double -bounded carbon atoms out of which, one has a substituent attached to it.
00:34
Now this substituent can be anything but we have taken methyl for just the sake of simplicity.
00:39
So when these kind of alkenes are subjected to a reaction or an addition reaction with polar molecules such as hbr, hcl, h2o, whatever it is, then the positively charged part or the hydrogen atom that is here is going to add up to the carbon that has the higher number of hydrogen atoms, while the negatively charged part is going to add up to the carbon that has the lower number of hydrogen atoms.
01:02
Hence, as per the marconikov's rule, the product which is going to be formed here would be ch3, chbr, and then ch2h.
01:11
So this is our product as per the marconikov's rule, and this product would have been called as anti -marconikov's product if the product was like this.
01:22
If the bromine atom, if the negatively charged part would have been added to the carbon having a higher number of hydrogen atoms, the product would have been called as an anti -marconicose product.
01:34
So here in the option b, what we have is cl ch double bond, ch2.
01:42
The reactant is clch double bond, ch2, and it is being treated with hcl molecule.
01:51
This is also a polar molecule just like hbr...