00:01
Hello students, in this question we have given speed that is n1 is given as 800 rpm.
00:10
We have given number of teeth that is t1 is equal to 2 and t2 is equal to 26.
00:19
Pitch diameter d is given 54 mm.
00:24
Pitch is given that is 18 mm.
00:31
Also coefficient of friction that is given as 0 .06.
00:37
Also the pressure angle will be equal to 3 .43 degree.
00:44
Now in this question we have three parts.
00:47
So in part 8 we have to find helix angle of worm gear.
00:51
So the helix angle of worm gear is equal to 90 degree minus lambda where lambda is a lead angle.
01:01
So lead angle for two start worm can be found by tan lambda is equal to 2p divided by 5d.
01:13
Now substituting the values we get 2 multiplied by 18 divided by 5 into 54.
01:22
After solving this we get 0 .212.
01:28
Now therefore lambda this is the tan lambda so lambda will be equal to 11 .98 degree.
01:43
Therefore the helix angle will be equal to 90 minus 11 .98 that is equal to 78 .02 degree.
02:02
Now for b part we have to find the speed of gear.
02:07
So to find the speed of gear pitch of wheel p2 is equal to axial pitch of worm that is 18 mm...