00:01
In this question we need to find v0 in the given circuit.
00:05
To do so we could find the v0 by first finding the voltage at node.
00:13
The first step is to find voltage.
00:16
We could write the kirchhoff's law that is kcl at node to find v which can be written as v -6 divided by 12k plus c multiplied by dv divided by dt plus v -0 divided by 6k is equal to 0.
01:09
Now we can write this as v -0 divided by 6k is equal to v divided by 1k plus 5k.
01:29
This is the current through the rightmost branch.
01:31
On solving further we can write it as dv divided by dt plus v divided by 4k multiplied by 100 mu minus 1 by 2k multiplied by 100 mu is equal to 0.
02:09
Therefore dv divided by dt plus v divided by 0 .4 minus 1 divided by 0 .2 is equal to 0.
02:33
On solving further we will get dv divided by dt plus 0 .5 volt is equal to 5.
02:52
Now we need to solve this differential equation to find v.
03:00
This differential equation is of the following form that is dy divided by dt plus py multiplied t is equal to q...