00:01
Hello student, in this problem, a schematic diagram of an industrial electronic sensing device is given.
00:08
And the system is working on the frequency of 2 kilohertz.
00:14
And we have to calculate the total impedance of the circuit looking from this side, zts.
00:21
And we know that the frequency of system f equals to 2 kilohertz, f equals to 2 kilohertz, or it is 2 into 2.
00:36
10 k power 3 huts.
00:40
Now we have to calculate the impedance of the system right.
00:43
So we assume that this branch having impedance z1, this branch having impedance z2 and this is impedance z 30.
00:53
So first we calculate the impedance of each branch.
00:56
So first we have to calculate z1, z1 equals to here the resistance and the capacitor are connected in series, the resistor and the capacitor are connected in series, then then the effect impedance will be 50 plus 1 upon j omega the capacitor is assume c so z1 equals to 50 plus 1 upon j and omega will be 2 into sorry omega equals to 2 pi f omega equals to 2 .5f, it will be 2 pi into frequency will 2 kilohertz.
01:43
It means 2 into 10k power 3.
01:51
Multiply the value of capacity is 2 micro -facred.
01:54
Then we have to convert the value in ferret.
01:57
Then it will be, it is 2 into 10k power minus 6.
02:03
Fine so the impedance z1 equals to 50 plus taking iota upside then the sign is changed plus 2 minus minus iota upon iota upon this value to pi into 2 x xx 2 k power 3 into 2 into 10 k power minus 6.
02:47
Now by solving this value z1 equals to 50 minus iota if you calculate the magnitude of this function then it will be 39 .787 fine this is the impedance z1 this is the impedance z1 okay now if you convert this value of this in rectangular form, in rectangular form, in rectangular form, then the value will be 63 .90 angle of minus 38 .5 .51.
03:45
So we can use further this value or this value for further calculation, right? and the impedance z2 equals to, now in branch z2 there are a inductor of 10 millinery and a register of 80 -oom...