Question

The decomposition of hydrogen peroxide in dilute sodium hydroxide at 20 °C H2O2(aq)?H2O(1) + 1/2O2(g) is first order in H2O2. During one experiment it was found that when the initial concentration of H2O2 was 5.48×10?² M, the concentration of H2O2 dropped to 1.28×10?² M after 838min had passed. Based on this experiment, the rate constant for the reaction is _____ min?¹ 

          The decomposition of hydrogen peroxide in dilute sodium hydroxide at 20 °C
H2O2(aq)?H2O(1) + 1/2O2(g)
is first order in H2O2.
During one experiment it was found that when the initial concentration of H2O2 was 5.48×10?² M, the concentration of H2O2 dropped to
1.28×10?² M after 838min had passed.
Based on this experiment, the rate constant for the reaction is
_____ min?¹
Show more…
The decomposition of hydrogen peroxide in dilute sodium hydroxide at 20 °C H2O2(aq)?H2O(1) + 1/2O2(g) is first order in H2O2. During one experiment it was found that when the initial concentration of H2O2 was 5.48×10?² M, the concentration of H2O2 dropped to 1.28×10?² M after 838min had passed. Based on this experiment, the rate constant for the reaction is min?¹

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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PLEASE HELP ASAP WILL LIKE!!14.4a duprewarsiduabedno/o axow.e The decomposition of hydrogen peroxide in dilute sodium hydroxide at 20c 1.2810-2Mafter838minhad passed. Based on this experiment,the rate constant for the reaction is HO(aqHOl+VOg is first order in HO ramsuy wuigns
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Transcript

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00:01 In this question, we are assigned to the task to calculate the rate constant of the reaction in minute inverse.
00:12 The initial concentration is given as 2 .38 into 10 raised to the power minus 2 molar.
00:24 The concentration at time t is given as 5 .95 into 10 raise to the power minus 2 molar.
00:33 3 molar, the time is given as 845 minutes.
00:40 Now for the first order reaction or the first order kinetics, k is equal to 2 .303 divided by t, log of initial concentration that is a node at time t.
01:06 In this case, initial concentration that is a0 is 2 .38 into 10 days to the power minus 2 and the concentration at time t is 5 .95 into 10 to the power minus 3...
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