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QUESTION 2 The 2-m-long tube is made of an elastic-perfectly plastic material as shown. a) Determine the applied torque T that subjects the material at the tube's outer edge to a shear strain of $\gamma_{max}$=0.005 rad. b) What would be the permanent angle of twist of the tube when this torque is removed? Sketch the residual stress distribution in the tube. Useful equations: $T = 2\pi \int \rho^2 \tau d\rho$ ; $\rho \cdot \phi = \gamma \cdot L$ ; $\phi = \frac{TL}{JG}$

          QUESTION 2
The 2-m-long tube is made of an elastic-perfectly plastic material as shown.
a) Determine the applied torque T that subjects the material at the tube's outer edge to a shear
strain of $\gamma_{max}$=0.005 rad.
b) What would be the permanent angle of twist of the tube when this torque is removed?
Sketch the residual stress distribution in the tube.
Useful equations: $T = 2\pi \int \rho^2 \tau d\rho$ ; $\rho \cdot \phi = \gamma \cdot L$ ; $\phi = \frac{TL}{JG}$

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QUESTION 2
The 2-m-long tube is made of an elastic-perfectly plastic material as shown.
a) Determine the applied torque T that subjects the material at the tube's outer edge to a shear
strain of γmax=0.005 rad.
b) What would be the permanent angle of twist of the tube when this torque is removed?
Sketch the residual stress distribution in the tube.
Useful equations: T = 2π∫ρ^2 τ dρ ; ρ·ϕ = γ· L ; ϕ = (TL)/(JG)

Added by Dustin G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Hast Aggarwal

01/10/2022

Step 1

Step 1: Calculate the polar moment of inertia (J) of the tube using the equation J = (pi/2)(d_o^4 - d_i^4), where d_o is the outer diameter and d_i is the inner diameter of the tube. Show more…

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Please help me quickly step by step. Thank you. QUESTION 2 The 2 m long tube is made of an elastic-perfectly plastic material as shown. a) Determine the applied torque T that subjects the material at the tube's outer edge to a shear strain of Yma-0.005 rad. b) What would be the permanent angle of twist of the tube when this torque is removed? Sketch the residual stress distribution in the tube. Useful equations: T=2pdp, p.=y.L : IG (50 pts) MPa 210 38 mm rad 32 mm 0.003

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