00:01
Hi, this is a question based on snell's law of refraction.
00:05
So, snell's law of refraction.
00:10
So, in the first part we have so here we have sin 45 degree divided by sin r1 is equal to 1 .62.
00:22
So, we have so here we have sin r1 is equal to sin 45 divided by 1 .62.
00:29
So, we have the value of r1 is equal to 25 .8 degree.
00:33
Similarly, we have for second refraction again we have so this is for first refraction then we have second refraction.
00:44
So, for second refraction we have sin r1 divided by sin r2 is equal to so sin r2 is equal to n1 by n2 1 .47 divided by 1 .62.
00:56
So, from this we have the value of r2 is equal to 28 .7 degree.
01:02
So, now the deviation is calculated as so we have the deviation of the light ray in the top layer is given by it is ab is equal to 2 into tan r1.
01:17
So, which is equal to 2 into tan of 25 .8 that is equal to 0 .970 centimeter.
01:25
Now we have the deviation on the bottom layer.
01:28
So, deviation on bottom layer is given by bc which is equal to 3 tan r2 that is equal to 3 into tan of 28 .7 which is equal to 1 .64 centimeter.
01:46
So, now we have the total distance d is equal to it is ab plus bc so which is the total deflection so that is equal to 2 .616 centimeter.
01:56
So, this is the first part.
01:57
So, the second part belongs to the polarization angle...