00:03
So this question is very long actually.
00:06
So let's look at the question a.
00:11
So for question a we needed to calculate the probability density function of x1, px1.
00:22
So we know that x0 could be x0 could be wrong or x0 could be 0.
00:38
And we also and we also know relationship x and the property x equals x and minus 1 .9 and the property x -end and the property x -m minus equals 1 minus 1 minus 1 0 .1 so so we can know that the possible the possible value for x1 is also could be either 1 or x1 or x1 could be zero and then we calculate the probability of these two cases so first x1 equals one and this could be calculated this way so when x1 equals 1 with condition xm equals x and x x and x is zero we have to be here to be x zero zero and this is 0 .5 and this is 0 .5.
02:24
And similarly, we can get p .x1 is 0 .5.
02:40
So we can have px1 .0 .5.
02:48
And also pf 1 with 0 .5.
02:53
So this is the probability.
02:56
Probability mass function.
03:07
And the question asks us to sew that pm, probability mass function is also true for xn.
03:27
And in order to sew this, we can assume, this is actually true.
03:36
So xn 0, with probability, point of 5 and also x1 with probably also 0 .5.
03:49
And then we calculate this, t x minus 1.
04:07
And we can get this is a t x around 0 with the condition x and also.
04:29
So this is 0 .5 .0 .9.
04:48
1 .5.
04:50
This is 1.
04:55
This is also can get when this guy is 1, the probability also 0 .5.
05:20
So we can get the pmf of x on platform is p .0, which is probably 1 .5.
05:42
So we can get that.
06:15
And then let's look at the question b.
06:20
The question b, in the first we calculate the mean of x.
06:27
So we denote this one as mu -x.
06:31
And this one could be as when this combination of this combination of this so x n times p x and so we can know that this is 25 and the when action is 0 times p x and the when plus when action is 1 times p x is 1 so this actually is 1 multiplied 25 and then we calculate the the covariance, co -variance to be written as the mean x and since x and then xm, the possible value either is 0 or 1.
08:02
So the combination of action multiply xm either could be 0 or 1.
08:10
So we can know that when we only consider when it's 1.
08:17
1 multiply p xm is 1 and also p xm is 1 right and minus 0 .5 and this is 0 when this is 0 .5.
08:46
On our one also quantifies .5 minus 0.
09:00
So we can know that action is not obviousness.
09:15
And for question c, we already know the mean of accidents on 5.
09:25
And then we calculate the variance of x -in.
09:33
The variance of x -in.
09:35
X in is written as x -m minus n ux...