00:02
Okay, so the laser beam of problem 64 has power of 2 .5 millawatts and a diameter of 3 .4 millimeters.
00:23
So in this problem, we want to calculate how much energy does a surface there was absorbing the light.
00:37
Receive in 12 seconds.
00:39
So we have a time of 12 seconds and we want to calculate how much energy is absorbed.
00:50
So okay let's remember that the energy for definition is the it's just the power multiply by the time.
01:04
Therefore we can say that the power of this laser which is 2 .5 times 10 to the minus 3 because we have a milli watts in here remember mealy watts in here is going to be multiply by 12 seconds therefore we have that the energy absorber by the surface is just 0 .03 jails that's the answer to the first item the second item we want to calculate the radiation pressure exerted by the beam.
01:46
So, okay, this is a little difficult, but we just need to go in the chapter and get back the equation.
01:54
So we know that the pressure, pressure is going to be equal the average intensity divided by c...