Question

Fluid coming out of a pipe has a volumetric flow rate of ? = 7.31×10? m³/s (I'm only using this variable name for convenience in your partial credit work). At the outlet, the diameter of the pipe is d? = 1.00 cm. Further back from the outlet but at the same height is a different diameter pipe where d? = 5.05 cm. Above this outlet a distance h is another pipe of diameter d? = 7.81 cm. This is indicated in the picture here. d?, P? h d?, P? d?, P? We also know P? – P? = P?? = -5.69 kPa and P? – P? = P?? = -53.7 kPa. a. (Q7 ans 2 pts, Q8 work 5 pts) What is the velocity of the fluid at point 3? b. (Q9, 7 pts) What is the velocity of the fluid at point 2? c. (Q10, 7 pts) What is the density of the fluid? (As a hint, you only need points 2 and 3 for this). d. (Q11, 7 pts) What is the height difference between points 1 and 2, called h in this picture? To continue, please give the fluid velocity at point 3 (part a) in units of m/s.

          Fluid coming out of a pipe has a volumetric flow rate of ? = 7.31&#215;10? m&#179;/s (I'm only using this
variable name for convenience in your partial credit work). At the outlet, the diameter of the pipe is
d? = 1.00 cm. Further back from the outlet but at the same height is a different diameter pipe where
d? = 5.05 cm. Above this outlet a distance h is another pipe of diameter d? = 7.81 cm. This is
indicated in the picture here.
d?, P?
h
d?, P? d?, P?
We also know P? – P? = P?? = -5.69 kPa and P? – P? = P?? = -53.7 kPa.
a. (Q7 ans 2 pts, Q8 work 5 pts) What is the velocity of the fluid at point 3?
b. (Q9, 7 pts) What is the velocity of the fluid at point 2?
c. (Q10, 7 pts) What is the density of the fluid? (As a hint, you only need points 2 and 3 for this).
d. (Q11, 7 pts) What is the height difference between points 1 and 2, called h in this picture?
To continue, please give the fluid velocity at point 3 (part a) in units of m/s.

Show more…

Fluid coming out of a pipe has a volumetric flow rate of ? = 7.31 #215;10? m #179;/s (I'm only using this
variable name for convenience in your partial credit work). At the outlet, the diameter of the pipe is
d? = 1.00 cm. Further back from the outlet but at the same height is a different diameter pipe where
d? = 5.05 cm. Above this outlet a distance h is another pipe of diameter d? = 7.81 cm. This is
indicated in the picture here.
d?, P?
h
d?, P? d?, P?
We also know P? – P? = P?? = -5.69 kPa and P? – P? = P?? = -53.7 kPa.
a. (Q7 ans 2 pts, Q8 work 5 pts) What is the velocity of the fluid at point 3?
b. (Q9, 7 pts) What is the velocity of the fluid at point 2?
c. (Q10, 7 pts) What is the density of the fluid? (As a hint, you only need points 2 and 3 for this).
d. (Q11, 7 pts) What is the height difference between points 1 and 2, called h in this picture?
To continue, please give the fluid velocity at point 3 (part a) in units of m/s.

Added by Daniel R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

10/25/2023

Step 1

The velocity of the fluid at point 3 can be calculated using the equation of continuity, which states that the product of the cross-sectional area (A) and the velocity (v) at any point along a pipe is constant. Show more…

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Fluid coming out of a pipe has a volumetric flow rate of m = 7.3110-3 m3/s (I'm only using this variable name for convenience in your partial credit work).At the outlet, the diameter of the pipe is d3 = 1.00 cm.Further back from the outlet but at the same height is a different diameter pipe where d2 = 5.05 cm.Above this outlet a distance h is another pipe of diameter d = 7.81 cm.This is indicated in the picture here. d1,P1 d2,P2 d3,P We also know P-P=P31=-5.69 kPa and P-P=P3=-53.7 kPa a. (Q7 ans 2 pts,Q8 work 5 pts) What is the velocity of the fluid at point 3? b. (Q9, 7 pts) What is the velocity of the fluid at point 2? c. (Q10, 7 pts) What is the density of the fluid? (As a hint, you only need points 2 and 3 for this) d. (Q11, 7 pts) What is the height difference between points 1 and 2, called h in this picture? To continue, please give the fluid velocity at point 3 (part a) in units of m/s

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Transcript

00:01 Hello students, for the a part diameter d3 is given as 1 cm.

00:10 So this will be equal to so radius r3 will be equal to d3 by 2 that will be equal to 5 into 10 raised to minus 3 meter and here the flow rate eta is given as 7 .31 into 10 raised to minus 3 meter cube per second, meter cube per second.

00:42 So according to equation of continuity, according to equation of continuity, according to equation of continuity flow rate eta should be constant at every points.

01:06 So flow rate should be constant.

01:11 So eta at point 3 at the pipe having diameter d3 will be equal to a3 into area into velocity, a3 is the area of the pipe that will be pi into 5 into 10 raised to minus 3 whole square into v3.

01:31 So v3 will be equal to eta divided by pi into 5 into 10 raised to minus 3 whole square.

01:41 So this will be equal to 7 .31 into 10 raised to minus 3 divided by pi into 5 into 10 raised to minus 3 whole square.

02:02 So if we calculate we will get velocity v3, this will be equal to 93 .12 meter per second.

02:11 So in the b part we have to find out the velocity for the pipe d2.

02:16 So diameter d2 is given as 5 .05 centimeter.

02:22 So radius r2 will be equal to 0 .0252 meter.

02:30 So flow rate eta will be equal to a2 into v2.

02:35 So velocity v2 will be equal to eta divided by area of cross section of pipe 2.

02:43 This will be equal to 7 .31 into 10 raised to minus 3 divided by pi into 0 .0252 whole square.

02:56 So if we calculate we will get the velocity v2 will be equal to 3 .66 meter per second.

03:08 So in the c part we have to find out the density rho.

03:15 So density rho density of the liquid will be equal to 1 by eta...

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