00:01
Hello students.
00:01
So for this video, we have to balance 15 reactions.
00:05
So the first reaction is h2 plus br2 giving rise to hbr.
00:10
So to balance this we have 2h and 2br here.
00:13
So we have to make it 2 here also.
00:15
So we will write 2 here.
00:17
Now it is balanced.
00:18
Then we have na2o plus h2o giving rise to naoh.
00:24
So we have 2, 2 each in this side.
00:27
So to make it 2 here, we will write 2 in front of it.
00:32
Then we have h2 plus n2 giving rise to nh3.
00:36
So firstly, we will balance the nitrogen.
00:38
So we will write 2 here and then we have 6 hydrogen here.
00:40
So to make it 6, we will write 3 here.
00:44
Then we have mclo3 giving rise to mcl plus o2.
00:49
So here firstly, we will make this even.
00:52
So we will write 2 here and to balance the mncl, we will write 2 here.
00:56
So we have 6 oxygen here.
00:58
So we will write here 3 to balance it.
01:01
Then we have h2o2 giving rise to h2o plus o2.
01:06
So we have firstly, we will make it even.
01:10
So oxygen even.
01:11
So we will write 2 here and now we have 4 hydrogen and 4 oxygen.
01:15
So to balance it, we will write 2 here.
01:18
Then we have h2co3 giving rise to h2o plus co2.
01:23
So as you can see 2h, 2h, 1c, 1c, 3o, 3o.
01:28
So it is already balanced.
01:31
Now next we have ch4 plus o2 giving rise to co2 plus water.
01:37
So firstly, we will balance the hydrogen.
01:41
So we have 4 hydrogen here.
01:43
So to balance it, we will write 2 here.
01:45
Now we have 4 oxygen.
01:47
So to balance it, we will write 2 here.
01:49
Carbon is already balanced.
01:52
Then we have c2h6 plus o2 giving rise to co2 plus water.
02:01
So firstly, what we will do is, we will first, we will try to make this even.
02:07
So to make this even, we have to write an even number.
02:10
But here we have 6 hydrogen.
02:11
So we will, to make it balanced, we will write 3.
02:17
So but it is not even.
02:18
So we will write 2 here to make it even.
02:20
So we can now write 6 here.
02:22
Now to balance the carbon, we have to write 4 here.
02:25
So we have 8 plus 6 total of 14 oxygen.
02:29
So to make it 14, we will write 7 here in the reactant side...