00:01
As far as i understand, there are two questions here.
00:03
So the test statistic value given, let's say this is the first question, the t value given, sorry, the z value is given here, which is negative 2 .83, and this is a two -tailed test.
00:15
And we have to find the p value.
00:17
First of all, let me draw the situation here.
00:19
This is the normal distribution.
00:21
So the z value here is negative 2 .83 and symmetrical value 2 .83.
00:26
And the area of this two shaded region just gives us the p value here.
00:30
So the p value, which is equal to, they are both symmetrical area.
00:35
So if i find the first area here and multiply by two, so this is two times the probability of z less than negative 2 .83.
00:44
Two times, in order to get this probability, i'm going to use the graphing display calculator application, normalcdf.
00:49
There is no lower boundary, put decimal number, upper boundary, and the mean value for z, which is the standard normal distribution variable, which is zero, and the standard division is one.
01:00
So this is two times.
01:02
I need normalcdf, press second variance, the second option, lower boundary, and the upper boundary, negative 2 .83, and the mean and the standard division here.
01:13
So the p value here is 0 .00 and 47.
01:18
This is the p value.
01:20
And the second question here, they are given the null hypothesis.
01:24
So the mu is 41 .175 and the alternative hypothesis, mu is greater than 41 .175...