Question

Q:1 What is the maximum frequency deviation of the following FM signal? x(t) = 15 cos(2.4 \times 10^8 \pi t + 5cos(2 \times 10^3 \pi t)) Q:2 What is the bandwidth of the following FM signal using Carson's rule? x(t) = 15 cos(2.4 \times 10^8 \pi t + 5sin(2 \times 10^3 \pi t))

          Q:1
What is the maximum frequency deviation of the following FM signal?
x(t) = 15 cos(2.4 \times 10^8 \pi t + 5cos(2 \times 10^3 \pi t))
Q:2
What is the bandwidth of the following FM signal using Carson's rule?
x(t) = 15 cos(2.4 \times 10^8 \pi t + 5sin(2 \times 10^3 \pi t))

Q:1
What is the maximum frequency deviation of the following FM signal?
x(t) = 15 cos(2.4 ×10^8 πt + 5cos(2 ×10^3 πt))
Q:2
What is the bandwidth of the following FM signal using Carson's rule?
x(t) = 15 cos(2.4 ×10^8 πt + 5sin(2 ×10^3 πt))

Added by Bradley M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Darshan Maheshwari

Step 1

In this case, we have two cosine terms with different frequencies: 2.4x10^6 Hz and 210x10^3 Hz. The maximum frequency deviation is equal to the difference between these two frequencies, so: Maximum frequency deviation = 2.4x10^6 Hz - 210x10^3 Hz = 2.19x10^6 Hz Show more…

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Please, I need a quick solution. Q:1 What is the maximum frequency deviation of the following FM signal? xt = 15cos(2.4x10^6t) + 5cos(210x10^3t) Q:2 What is the bandwidth of the following FM signal using Carson's rule? xt = 15cos(2.4x10^6t) + 5sin(2x10^6t)