Question

A rod of length I=0.9m and mass M= 3.8kg joins two particles with masses m? =3.8kg and m2 = 2.9kg, at its ends. The combination rotates in the xy- plane about a pivot through the center of the rod with the linear speed of the masses of v= 3.2 m/s. (Moment of inertia of a uniform rod rotating about its center of mass $I = \frac{1}{12}ML^2$) a) Calculate the total moment of inertia of the system I = kg m$^2$ b) What is the magnitude of the angular momentum about the origin? L= kg m$^2$/s c) If the length of the rod reduces to l=0.6m. What will be the final angular speed $\omega_f$? $\omega_f$ = ____ rad/s

          A rod of length I=0.9m and mass M= 3.8kg joins two particles with masses
m? =3.8kg and m2 = 2.9kg, at its ends. The combination rotates in the xy-
plane about a pivot through the center of the rod with the linear speed of the
masses of v= 3.2 m/s. (Moment of inertia of a uniform rod rotating about its
center of mass $I = \frac{1}{12}ML^2$)
a) Calculate the total moment of inertia of the system
I = ____ kg m$^2$
b) What is the magnitude of the angular momentum about the origin?
L= ____ kg m$^2$/s
c) If the length of the rod reduces to l=0.6m. What will be the final angular
speed $\omega_f$?
$\omega_f$ = ____ rad/s

A rod of length I=0.9m and mass M= 3.8kg joins two particles with masses
m? =3.8kg and m2 = 2.9kg, at its ends. The combination rotates in the xy-
plane about a pivot through the center of the rod with the linear speed of the
masses of v= 3.2 m/s. (Moment of inertia of a uniform rod rotating about its
center of mass I = (1)/(12)ML^2)
a) Calculate the total moment of inertia of the system
I = kg m^2
b) What is the magnitude of the angular momentum about the origin?
L= kg m^2/s
c) If the length of the rod reduces to l=0.6m. What will be the final angular
speed ?
= rad/s

Added by Ignacio J.

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