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3. Write the profiles definition and NC code for the following part. Use linear and circular interpolation only. Speed = 2500RPM and Feed = 50mm/minutes. (10 points).

          3. Write the profiles definition and NC code for the following part. Use linear and circular interpolation only. Speed = 2500RPM and Feed = 50mm/minutes. (10 points).
        
3. Write the profiles definition and NC code for the following part. Use linear and circular interpolation only. Speed = 2500RPM and Feed = 50mm/minutes. (10 points).

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Please provide the correct answer with all steps shown. Thank you! 3. Write the profile's definition and NC code for the following part. Use linear and circular interpolation only. Speed = 2500 RPM and Feed = 50 mm/minute. (10 points). 130 0.110 15 (40,30) BD,20 20 0.0 >X {60,0} 8 50
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Transcript

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00:01 Hello, in the question we have to calculate the speed for each segment on the graph.
00:06 So they have given the segment a, this segment is b, this segment is c, d and e.
00:12 So we have to calculate for each segment the speed.
00:17 So now this is the rough schematic of the graph which i have drawn over here.
00:23 So now for segment a, so they have also given the time.
00:27 So for time t is equals to 0 to 10 seconds.
00:36 So that is segment.
00:41 So we will use the formula over here.
00:43 So this coordinate, i will call it as x.
00:47 So the final one, so this final one, i'm calling it as x2 and the initial one, i'm calling it as x1.
00:54 So this one is x2, this one is x1.
01:02 So velocity is x2 minus x1 divided by t2 minus t1.
01:09 So for this one, i will do and for the others one, we will just recite.
01:16 So x2 over here is 60, x1 over here is 0, then t2 is 10 and t1 over here is 0.
01:29 So from here only we are doing, so 10 minus 0.
01:32 For every problem, for further all the things, we are going to do this only.
01:37 So let us plug the value then.
01:39 So this v will be equal to, so this is for segment a.
01:43 So let me write it as va.
01:44 So x2 is 60 minus 0 divided by t2 minus t1.
01:49 We will call it as delta t from henceforth.
01:52 So this will be 10.
01:53 So 60 divided by 10 is nothing but 6 meters per second.
01:58 So this is va.
02:00 Now for t is equal to 10 to 15 seconds.
02:05 So now see x2 and x1 is same.
02:10 So this is my x2, this is my x1.
02:13 So x2 and x1 is same.
02:14 So x2 minus x1 is 0.
02:16 So this velocity, so this is my segment b.
02:23 So for segment b, this velocity is 0.
02:26 Now for t is equal to 15 to 30 seconds, that is segment.
02:39 So now see this will be x2.
02:42 So for this c segment, this is x2, this is my x1.
02:46 So it is, so x2 is 0.
02:49 So i will write over here x2 is 0 and x1 is 60 and time delta t will be 30 minus 15, that is 15...
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